//find a year is leap year or not
#include "stdio.h"
int main ()
{
int yr;
printf ("Enter the year:\n");
scanf ("%i",&yr);
if (yr>=1000 && yr%4==0)
{
printf (" %d is a leap year \n",yr);
}
else if (yr>=1000 && yr%4!=0)
{
printf ("%i is not a leap year \n",yr);
}
else if (yr<1000)
{
printf ("Enter a vaid year that is greter than 1000\n");
}
return 0;
}
output output output
Enter the year:
2023
2023 is not a leap year
or
Enter the year:
2024
2024 is a leap year
or
Enter the year:
999
Enter a vaid year that is greter than 1000
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